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T O P I C R E V I E W
Voivoid
Posted - Sep 10 2013 : 02:34:28 AM Consider the following code:
static const int val = 42;
int main() {
int tmp = val;
int val = 0;
return val;
}
Move cursor to the line 'return val;'. Try refactor-rename to rename 'val' variable. 'int tmp = val' line changes though it should not.
static const int val = 42;
int main() {
int tmp = val_new;
int val_new = 0;
return val_new;
}
VA 10.7.1949.0
3 L A T E S T R E P L I E S (Newest First)
accord
Posted - Sep 12 2013 : 2:21:41 PM Basically, when you define an outer and inner scope variable with the same name, it always fails, I mentioned the cases in the bug report. Thank you for the sample, though.
Voivoid
Posted - Sep 12 2013 : 08:27:41 AM A few more cases:
int main() {
int n = 0;
for( int n = 0; n < 10; ++n ) {
}
++n;
return 0;
}
1) Move cursor to
int n = 0
Try to rename 'n'. The following line changes though it should not
for( int n = 0; n < 10; ++n ) {
2) Move cursor to
for( int n = 0; n < 10; ++n ) {
Try to rename 'n'. The following line changes though it should not
int n = 0
accord
Posted - Sep 10 2013 : 5:34:44 PM I am seeing the same effect here. Thank you for the clear description.
