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daThomas
Junior Member
15 Posts |
 Posted - Jan 31 2006 : 04:32:32 AM
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Hi,
i use strings to define layerstacks for views. It would be very cool to see the corresponding bracket when editing these strings. is taht possible?
example:
"PlaneTransformation(Prototype(viewingant::DefaultSliceSetWidthPlaneTransformation))"
"SliceSetAccessor(Prototype(viewingant::SliceSetAccessor))"
"Trackable(Prototype(ThreeDTrackable)))"
"pimp3d::ZBuffer3DPlacementLayer("
"pimp3d::ThreeDTrackableDraggingInterstateLayer()"
"viewingant::ThreeDPlaneViewLayerSwitchLayer("
"viewingant::ThreeDPlaneViewLayer())))"
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jpizzi
Tomato Guru
USA
642 Posts |
Posted - Jan 31 2006 : 10:45:40 PM
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| One possibility would be to construct the strings without the quotes, then add them after completion, using the 'surround with ""' feature. VA should highlight matching brackets during the construction, then you have your quotes, like you need afterwards. |
Joe Pizzi |
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feline
Whole Tomato Software
United Kingdom
19003 Posts |
Posted - Feb 01 2006 : 4:04:24 PM
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unfortunately VA does not have a surround with double quotes feature. there was a discussion about this a while ago, and no one could come up with a solid reason for this, until now 
i have certainly constructed strings without the double quotes to get this sort of help myself before now. plus with a bit of care you should be able to use find and replace in regular expression mode to insert the double quotes for you once you are finished. |
zen is the art of being at one with the two'ness |
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jpizzi
Tomato Guru
USA
642 Posts |
Posted - Feb 01 2006 : 9:06:40 PM
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For the find and replace expression, if you first highlight the code you want "string-ified", you can use the following find and replace strings:
find what: ^{.+}$
replace with: "\\1"
Note: the second one _does_ include the quotes (unlike many examples that people give). |
Joe Pizzi |
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feline
Whole Tomato Software
United Kingdom
19003 Posts |
Posted - Feb 02 2006 : 4:13:40 PM
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interesting! reading that i can see what you are doing, even though i am not familiar with the \\1 notation. having just tried it, since i am curious, in VS2003 doing a find and replace "using regular expression" i am being told the search string cannot be found *puzzled*
how can "one or more of any character" not be found in a selected block of text? |
zen is the art of being at one with the two'ness |
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jpizzi
Tomato Guru
USA
642 Posts |
Posted - Feb 02 2006 : 11:13:18 PM
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Well, I took this right out of the find and replace dialog in VS 2003, too.
Maybe there is something from the web disturbing it? The find string was constructed from:
Beginning of line
Tag expression
Any character
One or more times
(move the cursor outside the braces)
End of line
The replace with string is:
double quote
Tagged expression 1
double quote
Make sure you have the "Use:" set to "Regular expressions". With the exception of the quotes, everything was selected off the right-pointing arrow after the drop-down of the combo box.
Oh, I just realized what might be the issue: This find-and-replace is setup to only do complete lines (the ^ at the front and the $ at the back). If you didn't have an entire line selected, it wouldn't work. For an arbitrary selection, drop the ^ and $ from the find what text. |
Joe Pizzi |
Edited by - jpizzi on Feb 02 2006 11:15:37 PM |
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feline
Whole Tomato Software
United Kingdom
19003 Posts |
Posted - Feb 04 2006 : 2:50:09 PM
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most odd. i had made the wild assumption that since i had told find and replace to operate on the selection only that the ^ and $ codes would apply to the start and end of the selection. not a bad theory, but not valid.
testing this with whole lines selected it works perfectly, just as expected. however even after removing the ^ and $ i am getting "not found" when trying this on a piece of text in the middle of a line. i am probably going to have to look up the help on the find and replace regex syntax at some point. |
zen is the art of being at one with the two'ness |
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jpizzi
Tomato Guru
USA
642 Posts |
Posted - Feb 05 2006 : 12:08:01 AM
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Interesting. I just tried it myself, and you are right, it doesn't work. My guess is that since the expression will match EVERYTHING, it assumes that isn't right, so doesn't match. Actually, when I tried it, it matches something later. I couldn't determine what the criteria for the match really was.
It might be that for an arbitrary selection, a macro might be better. For the O/P's example, however, my regex should work just fine. His (her?) example had numerous strings as complete lines. |
Joe Pizzi |
Edited by - jpizzi on Feb 05 2006 12:08:23 AM |
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feline
Whole Tomato Software
United Kingdom
19003 Posts |
Posted - Feb 06 2006 : 1:02:46 PM
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very true, and definitely an interesting solution.
this is the problem i have with regular expressions, they seem to be slightly different in every program that supports them *rolls eyes* |
zen is the art of being at one with the two'ness |
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matching )]} in strings
