If I type a semicolon at this point, the resulting text should be: myString.Trim(); instead of myString.Trim(;)
I have to admit that this "error" is really irritating.
Think about it. There are several functions like Trim(), with default parameters. A semicolon will never be valid in that context (except inside a string constant).
Improvement
Posted - Jan 15 2008 : 2:11:27 PM
