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Goto Definition fails on explicit operator bool

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T O P I C R E V I E W
Kram	Posted - Oct 08 2021 : 10:56:23 AM Hello, Goto Definition works if the cursor is on the operator keyword but not the bool keyword. namespace test_2 { class c { public: operator bool() const { return b; } bool b; }; bool g(const c& p) { return p.operator bool(); } }
3 L A T E S T R E P L I E S (Newest First)
feline	Posted - Oct 11 2021 : 1:34:22 PM I didn't know you could call overloaded operators explicitly like this, but it makes sense, seeing it done and running some tests on it here. I am not entirely sure that this is a bug, since in general using alt-g on the keyword "bool" doesn't make any sense, but since it is part of the operator, and it is the function name, I have put in a bug report for this. But this does illustrate the general point that Alt-g on overloaded operators is a bit tricky. case=146308
Kram	Posted - Oct 08 2021 : 1:13:02 PM Nothing clever, it's just explicitly calling the operator bool. I use it mainly during Native Unit Tests as the Assert::IsTrue / IsFalse won't accept a std::shared_ptr without an explicit conversion. This is due to the explicit operator bool declaration. I suppose that I could have just cast it.
feline	Posted - Oct 08 2021 : 12:03:28 PM I am seeing the same thing here. At the risk of asking a silly question, what is "operator bool()" doing? Are you actually overloading casting the class to a bool, or is this doing something else? Plus, I don't think I have ever seen an overloaded operator called like that before. Just when you think you are starting to get to grips with C++

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