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 Goto Definition fails on explicit operator bool		  New Topic  Reply to Topic
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Kram
Junior Member

Germany
16 Posts
Posted - Oct 08 2021 :  10:56:23 AM  Show Profile  Reply with Quote
Hello,

Goto Definition works if the cursor is on the operator keyword but not the bool keyword.

namespace test_2
{
    class c
    {
    public:
        operator bool() const {
            return b;
        }

        bool b;
    };

    bool g(const c& p)
    {
        return p.operator bool();
    }
}
B00ting, please wait...
Edited by - Kram on Oct 08 2021 10:57:10 AM

feline
Whole Tomato Software

United Kingdom
18749 Posts
Posted - Oct 08 2021 :  12:03:28 PM  Show Profile  Reply with Quote
I am seeing the same thing here. At the risk of asking a silly question, what is "operator bool()" doing? Are you actually overloading casting the class to a bool, or is this doing something else?

Plus, I don't think I have ever seen an overloaded operator called like that before.

Just when you think you are starting to get to grips with C++
zen is the art of being at one with the two'ness
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Kram
Junior Member

Germany
16 Posts
Posted - Oct 08 2021 :  1:13:02 PM  Show Profile  Reply with Quote
Nothing clever, it's just explicitly calling the operator bool.
I use it mainly during Native Unit Tests as the Assert::IsTrue / IsFalse won't accept a std::shared_ptr without an explicit conversion. This is due to the explicit operator bool declaration. I suppose that I could have just cast it.
B00ting, please wait...
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feline
Whole Tomato Software

United Kingdom
18749 Posts
Posted - Oct 11 2021 :  1:34:22 PM  Show Profile  Reply with Quote
I didn't know you could call overloaded operators explicitly like this, but it makes sense, seeing it done and running some tests on it here.

I am not entirely sure that this is a bug, since in general using alt-g on the keyword "bool" doesn't make any sense, but since it is part of the operator, and it is the function name, I have put in a bug report for this. But this does illustrate the general point that Alt-g on overloaded operators is a bit tricky.

case=146308
zen is the art of being at one with the two'ness
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