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1533: operators and the using declaration

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.oisyn
Tomato Guru

162 Posts

Posted - Sep 19 2006 : 08:43:03 AM

struct A
{
	void foo();
	void operator[](int) const { }
};

struct B : public A
{
	using A::foo;
	using A::operator[]; // #1
};

The keyword 'operator' in #1 shows with a red underline for some reason. Using the using declaration with regular functions works fine.

feline
Whole Tomato Software

United Kingdom
18939 Posts

Posted - Sep 23 2006 : 5:08:16 PM

confirmed.

case=2674

i had to go and look that one up to work out what you were doing

zen is the art of being at one with the two'ness

.oisyn
Tomato Guru

162 Posts

Posted - Sep 26 2006 : 07:02:21 AM

For the record ;) :

Well in my example it is pointless of course, but it's used to unhide base members if you're implementing the same function with a different signature in a derived class.

struct Base
{
    void operator() (int);
};

struct Derived : public Base
{
    using Base::operator();         // #1
    void operator() (const char *); // #2
};

void foo()
{
    Derived d;
    d(123);  // isn't possible without #1 as #2 hides all base members with the same name.
}